Question

At ${127}^0$C and $1$ atm. pressure, a mixture of gases contains $0.3$ mole of $N_2$, $0.2$ mole of $O_2$. The volume of the mixture is:

• A. $15$ lit
• B. $22.4$ lit
• C. $18.2$ lit
• D. $16.4$ lit

Answer 1

The correct option is D $16.4$ lit

$PV=\left(n_{total}\right)RT\left(1\right)\left(V\right)=(0.3+0.2)\left(0.0821\right)\left(400\right)=\left(0.5\right)\left(400\right)\left(0.0821\right)=2\times \left(8.21\right)=16.4litres$