At 18-C the mobilities of NH4- and ClO4- ions are 6-6- 10-4 and 5-7-10-4cm2 volt-1 sec-1 at infinite dilution- The equivalent conductance of ammonium chlorate solution is-

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Coagulation

At 18∘C the...

Question

At $18^{\circ} C$ the mobilities of $N H_{4}^{+}$ and $C l O_{4}^{-}$ ions are $6.6 \times 10^{- 4}$ and $5.7 \times 10^{- 4} c m^{2} v o l t^{- 1} s e c^{- 1}$ at infinite dilution. The equivalent conductance of ammonium chlorate solution is:

119.20 m h o c m^{- 1} e q^{- 1}

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117.14 m h o c m^{- 1} e q^{- 1}

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118.67 m h o c m^{- 1} e q^{- 1}

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Solution

The correct option is C $118.67 m h o c m^{- 1} e q^{- 1}$
From Kohlrausch's law. we have,
$Δ_{N H_{4} C l O_{4}}^{\circ} = λ_{N H_{4}^{+}}^{\circ} + λ_{C l O_{4}^{-}}^{\circ} = F u_{N H_{4}^{+}}^{\circ} + F u_{C l O_{4}^{-}}$
$Δ_{N H_{4} C l O_{4}}^{\circ} = F (u_{N H_{4}^{+}}^{\circ} + u_{C l O_{4}^{-}}^{\circ}) = 96500 (6.6 \times 10^{- 4} + 5.7 \times 10^{- 4})$
$Δ_{N H_{4} C l O_{4}}^{\circ} = 118.67 m h o c m^{2} e q^{- 1}$

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Similar questions

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At 18∘C the mobilities of NH+4 and ClO−4 ions are 6.6×10−4 and 5.7×10−4cm2volt−1sec−1 at infinite dilution. The equivalent conductance of ammonium chlorate solution is:

The correct option is C 118.67mhocm−1eq−1From Kohlrausch's law. we have,Δ∘NH4ClO4=λ∘NH+4+λ∘ClO−4=Fu∘NH+4+FuClO−4Δ∘NH4ClO4=F(u∘NH+4+u∘ClO−4)=96500(6.6×10−4+5.7×10−4)Δ∘NH4ClO4=118.67mhocm2eq−1

At $18^{\circ} C$ the mobilities of $N H_{4}^{+}$ and $C l O_{4}^{-}$ ions are $6.6 \times 10^{- 4}$ and $5.7 \times 10^{- 4} c m^{2} v o l t^{- 1} s e c^{- 1}$ at infinite dilution. The equivalent conductance of ammonium chlorate solution is: