Question

At ${25}^{\circ }C$, the solubility product of $CuCl$ is $2.0\times {10}^{-7}$ and $E_{C{l}^{-}|CuCl|Cu}^{\circ }$ is $0.128V$. The value of $E_{C{u}^{+}/Cu}^{\circ }$ is: $\left[\right(\log 2=0.3),(2.303RT/F=0.06$)]

• A. $-0.274V$
• B. $-0.402V$
• C. $+0.53V$
• D. $+0.402V$

Answer 1

The correct option is C $+0.53V$

$Ksp=2.0\times {10}^{-7}⟶Q$ $-lnQ=7-log2=6.7$

Nernst Equation

$E=E°-0.06\left[lnQ\right]$

$0.128+0.06\left[6.07\right]=E°$

$E_{{Cu}^{+}/Cu}^{\circ }=0.53V$