Question

If same quantity of electricity is passed through $CuCl$ and ${CuSO}_4$, the ratio of the weights of $Cu$ deposited from ${CuSO}_4$ and $CuCl$ is :-

• A. $2:1$
• B. $1:2$
• C. $1:1$
• D. $4:1$

Answer 1

The correct option is B $1:2$

If same quantity of electricity is passed through $CuCl$ and $CuS{O}_4$, the ratio of the weights of $Cu$ deposited from $CuS{O}_4$ and $CuCl$ is $1:2$.

$2$ moles of electrons will deposit $1$ mole of $Cu$ from $CuS{O}_4$ whereas $2$ moles of electrons will deposit $2$ moles of $Cu$ from $CuCl$. This is because the valence of $Cu$ in $CuS{O}_4$ and $CuCl$ is $2$ and $1$ respectively.