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Equivalent, Molar Conductivity and Cell Constant

At 25oC for t...

Question

At $25^{o} C$ for the given cell,

$A g (s) | A g^{+} (a q, x M) | | A g^{+} (a q, 1.0 M) | A g (s)$

$E_{c e l l} = 0.26 V$
What will be the value of ${log}_{10} (x)$ ?
Here $x$ is the concentration of electrolyte

- 2.2

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+ 2.2

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+ 4.4

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- 4.4

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Solution

The correct option is D $- 4.4$
$A g | A g^{+} (x M) | | A g^{+} (1.0 M) | A g$

For the given cell representation, the cell reaction will be,
$A g^{+} (a q, 1 M) \to A g^{+} (a q, x M)$

$E_{c e l l} = E^{0} - \frac{0.0592}{1} l o g \frac{x}{1.0}$

For concentration cells, cathode and anode consist of same metal and its solution.
Thus,
$E^{0} = 0$

$0.26 = 0 - 0.059 log (\frac{x}{1.0})$

${log}_{10} (x) = \frac{0.26}{- 0.059} \approx - 4.4$

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