At 25oC- the ionic mobility of CH3COO- H- are respectively 4-1- 10-4- 3-63-10-3 cm-sec the conductivity of 0-001 M CH3COOH is 5-10-5S-cm-1- Dissociation constant of CH3COOH is -

Dissociation constant of CH_3COOH = α α = λ_m^cλ_m^0 λ_m(CH_3COOH)^I=λ_m(CH_3COO^ )^I+λ_m(H^+)^I #160; #160; #160; #160; #160;I = ...

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Byju's Answer

Standard XII

Chemistry

Polarisability and Fajan's Rule

At 25oC, th...

Question

At $25^{o} C$ , the ionic mobility of $C H_{3} C O O^{-}$ , $H^{+}$ are respectively $4.1 \times 10^{- 4}$ , $3.63 \times 10^{- 3} c m / s e c$ the conductivity of $0.001 M C H_{3} C O O H$ is $5 \times 10^{- 5} S . c m^{- 1}$ . Dissociation constant of $C H_{3} C O O H$ is :

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Solution

Dissociation constant of $C H_{3} C O O H = α$
$α = \frac{λ_{m}^{c}}{λ_{m}^{0}}$
$λ_{m (C H_{3} C O O H)}^{I} = λ_{m (C H_{3} C O O^{-})}^{I} + λ_{m (H^{+})}^{I}$ I = infinite
$= 4.1 \times 10^{- 4} + 3.63 \times 10^{- 3}$
$= 4.04 \times 10^{- 3}$
$α = \frac{5 \times 10^{- 5}}{4.04 \times 10^{- 3}}$

$α = 0.012$ 0r 1.2%

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At 25oC, the ionic mobility of CH3COO−, H+ are respectively 4.1×10−4, 3.63×10−3cm/sec the conductivity of 0.001MCH3COOH is 5×10−5S.cm−1. Dissociation constant of CH3COOH is :

Dissociation constant of CH3COOH=αα=λcmλ0mλIm(CH3COOH)=λIm(CH3COO−)+λIm(H+) I = infinite=4.1×10−4+3.63×10−3=4.04×10−3α=5×10−54.04×10−3α=0.012 0r 1.2%

At $25^{o} C$ , the ionic mobility of $C H_{3} C O O^{-}$ , $H^{+}$ are respectively $4.1 \times 10^{- 4}$ , $3.63 \times 10^{- 3} c m / s e c$ the conductivity of $0.001 M C H_{3} C O O H$ is $5 \times 10^{- 5} S . c m^{- 1}$ . Dissociation constant of $C H_{3} C O O H$ is :