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Question

At 2500C and 1 atm pressure, the v.d. of PCl5 is 57.9 Calculate

(i) Kp for the reaction (ii) % dissociation when P is doubled.

Find X=i+ii

The answer X must be an integer.

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Solution

PCl5 PCl3 + Cl2

(V.d.)obs. = 57.9
Mmixture = 2×57.9 = 115.8

Observed mol.wt. = Theoretical mol.wt.Total no.of moles

Mmixture = Mth[1+(n1)α] = 208.51+α α = 0.8

Kp = α2P1α2 = 169=1.7

When P is doubled,
169 = Kp = (a)21(a)2P [ P = 2atm]

a = 0.69 (ii) Ans.

Therefore, X=i+ii

X=1.7+0.69=2.392

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