At 27- C and 1 atmosphere pressure N2O4 is 20

The correct option is C 0.166The dissociation equilibrium is N_2O_4 ⇔ 2NO_2 .At equilibrium, N_2O_4 is 20 ...

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Byju's Answer

Standard XII

Chemistry

Derivation of Kp and Kc

At 27∘ C an...

Question

At $27^{\circ} C$ and 1 atmosphere pressure $N_{2} O_{4}$ is 20% dissociated into $N O_{2}$ . Find $K_{p}$ .

0.2

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0.166

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0.15

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0.1

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Solution

The correct option is C 0.166
The dissociation equilibrium is $N_{2} O_{4} \Leftrightarrow 2 N O_{2}$ .
At equilibrium, $N_{2} O_{4}$ is 20% dissociated.
Total pressure is 1 atm. Assum initially 1 mole of $N_{2} O_{4}$ is present.

The following table lists the equilibrium pressures of various species.

$N_{2} O_{4}$
$N O_{2}$
Initial moles
1
0
Change in moles
-0.2
0.4
Equilibrium moles
0.8
0.4
Equilibrium partial pressures
0.667
0.333
The expression for the equilibrium constant becomes $K_{p} = \frac{P_{N O_{2}}^{2}}{P_{N_{2} O_{4}}} = \frac{(0.333)^{2}}{0.667} = 0.166$ .

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	$N_{2} O_{4}$	$N O_{2}$
Initial moles	1	0
Change in moles	-0.2	0.4
Equilibrium moles	0.8	0.4
Equilibrium partial pressures	0.667	0.333

At 27∘C and 1 atmosphere pressure N2O4 is 20% dissociated into NO2. Find Kp.

At $27^{\circ} C$ and 1 atmosphere pressure $N_{2} O_{4}$ is 20% dissociated into $N O_{2}$ . Find $K_{p}$ .