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At 298K the m...

Question

At 298K the molar conductivities at infinite dilution ( $_{m}$ ) of $N H_{4} C l$ , KOH and KCl are 152.8, 272.6 and 149.8 $S c m^{2} m o l^{- 1}$ respectively. The $_{m}$ of $N H_{4} O H$ is $S c m^{2} m o l^{- 1}$ and % dissociation of 0.01 M $N H_{4} O H$ with $λ_{m} = 25.15 c m^{2} m o l^{- 1}$ at the same temperature are

275.6, 0.91

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275.6, 9.1

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266.6, 9.6

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30, 84

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Solution

The correct option is C 275.6, 9.1

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Similar questions

Λ_{m}^{\circ}

{N H}_{4} C l, K O H

K C l

S

{c m}^{2} {m o l}^{- 1}

Λ_{m}^{\circ}

{N H}_{4} O H

S

{c m}^{2} {m o l}^{- 1}

{N H}_{4} O H

Λ_{m} = 25.1 S {c m}^{2} {m o l}^{- 1}

λ_{m}^{\infty}

λ_{m}^{\infty}

(H C l)

= 426

S c m^{2} m o l^{- 1}

λ_{m}^{\infty}

(N a C l)

= 126

S c m^{2} m o l^{- 1}

λ_{m}^{\infty} (C H_{3} C O O N a) = 91

S c m^{2} m o l^{- 1}

_{m}

= 425.9 Ω^{- 1} c m^{2} m o l^{- 1}

_{m}

= 126.4 Ω^{- 1} c m^{2} m o l^{- 1}

_{m}

= 91 Ω^{- 1} c m^{2} m o l^{- 1}

Ω^{- 1} c m^{2} m o l^{- 1}

N a C l

H C l

C H_{3} C O O N a

S c m^{2} m o l^{- 1}

C H_{3} C O O H

λ_{m}^{\infty}

N H_{4} O H

λ_{m}^{\infty} for B a (O H)_{2} = 457.6 o h m^{- 1} c m^{2} m o l^{- 1} .

λ_{m}^{\infty} for B a (C l_{2}) = 240.6 o h m^{- 1} c m^{2} m o l^{- 1} .

λ_{m}^{\infty} for N H_{4} C l = 128.8 o h m^{- 1} c m^{2} m o l^{- 1} .

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