At 5270- the reaction NH3g-1-2N2g - 3-2H2g has Kc - 4 then what is the value of kp for the same reaction-

The correct option is B 4×(800 R)^1 NH _ 3 ( g ) ⇌ 1/2 N _ 2 ( g ) +3/2 H _ 2 ( g ) T= 527 ^ 0 C, K _ C =4 We know that K _ P = K _ C ( RT ) ...

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Derivation of Kp and Kc

At 5270, th...

Question

At $527^{0}$ , the reaction $N H_{3} (g) ⇌ \frac{1}{2} N_{2} (g) + \frac{3}{2} H_{2} (g)$ has $K_{c}$ = 4 then what is the value of $k_{p}$ for the same reaction?

4 \times (800 R)^{1}

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(\frac{800 R}{4})^{- 2}

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(\frac{1}{4 \times 800 R})^{2}

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None of these

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Solution

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Similar questions

527^{o} C

K_{c} = 4

N H_{3} (g) ⇌ \frac{1}{2} N_{2} (g) + \frac{3}{2} H_{2} (g)

K_{p}

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

527^{0}

N H_{3} (g) ⇌ \frac{1}{2} N_{2} (g)

\frac{3}{2} H_{2} (g)

K_{c} = 4

K_{c}

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

527^{\circ} C

K_{c} = 4

N H_{3} (g) ⇌ \frac{1}{2} N_{2} (g) + \frac{3}{2} H_{2} (g)

K_{P}

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

K_{p}

N_{2} (g) + 3 H_{2} (g) ⇌ 2 {N H}_{3} (g)

298 K

5.2 \times 10^{- 5}

K_{c}

298 K

\frac{1}{2} N_{2} (g) + \frac{3}{2} H_{2} (g) ⇌ {N H}_{3} (g)

Δ G^{o}

\frac{1}{2} N_{2} (g) + \frac{3}{2} H_{2} (g) ⇌ {N H}_{3} (g); K_{p} = 4.42 \times 10^{4}

25^{o} C

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