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Derivation of Kp and Kc

At 60o and ...

Question

At $60^{o}$ and 1 atm of $N_{2} O_{4}$ is 50% dissociated into $N O_{2}$ then Kp is:

A

1.33 atm

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B

2 atm

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C

2.67 atm

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D

3 atm

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Solution

The correct option is C 2 atm
$N_{2} O_{4} ⇌ {2 N O}_{2} i n i t i a l a m t . 1 - A t e q^{m} 1 - 0.05 0.50 \times 2 K_{P} = \frac{{(0.50 \times 2)}^{2}}{0.50} = 2 a t m$

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Similar questions

60^{o}

N_{2} O_{2}

is 50% dissociated into

N O_{2}

K_{p}

60^{\circ}

1 a t m

N_{2} O_{4}

50

% dissociated into

N O_{2}

K_{p}

60^{o} C

N_{2} O_{4}

50 %

N O_{2}

K_{p}

27^{o} C

and 1 atm pressure,

N_{2} O_{4}

is 20% dissociation into

N O_{2}

. What is the density of equilibrium mixture of

N_{2} O_{4}

N O_{2}

27^{o} C

340

1

N_{2} O_{4}

66 %

dissociated into

N O_{2}

. What volume does

10

N_{2} O_{4}

occupy under these conditions?

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