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Question

At 700 K, the equilibrium constant Kp, for the reaction
2SO3(g)2SO2(g)+O2(g)
is 1.8×103kPa. What is the numerical value of KC for this reaction at the same temperature?
R=0.0821 L atm mol1 K1

A
3.09×107 mole litre1
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B
9.03×107 mole litre1
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C
5.05×109 mole litre1
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D
5.05×105 mole litre1
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Solution

The correct option is A 3.09×107 mole litre1
We know the relationship
KP=KC(RT)n
Here KP=1.80×103
KP=1.8×103101.3atm
=1.78×105 atm
R=0.0821 litre atm K1 mol1
n=32=1
T=700 K
KC=KP(RT)n
putting the values,
KC=1.78×1050.0821×700
=3.09×107 mole litre1.

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