At 700 K, the equilibrium constant Kp, for the reaction 2SO3(g)⇌2SO2(g)+O2(g)
is 1.8×10−3kPa. What is the numerical value of KC for this reaction at the same temperature? R=0.0821Latmmol−1K−1
A
3.09×10−7molelitre−1
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B
9.03×10−7molelitre−1
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C
5.05×10−9molelitre−1
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D
5.05×10−5molelitre−1
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Solution
The correct option is A3.09×10−7molelitre−1 We know the relationship KP=KC(RT)△n
Here KP=1.80×10−3 KP=1.8×10−3101.3atm =1.78×10−5atm R=0.0821 litre atm K−1mol−1 △n=3−2=1 T=700K KC=KP(RT)△n
putting the values, KC=1.78×10−50.0821×700 =3.09×10−7molelitre−1.