MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Relation between Kp and Kc

At 800∘C, the...

Question

At $800^{\circ}$ C, the following equilibrium is established as
$F_{2} (g) ⇌ 2 F (g)$
The composition of equilibrium may be determined by measuring the rate of effusion of the mixture through a pin hole. It is found that at $800^{\circ}$ C and 1 atm mixture effuses 1.6 times as fast as $S O_{2}$ effuses under the similar conditions. (Atomic weight of F =19 amu). What is the value of $K_{p}$ ?

A

0.315 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

0.685 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

0.460 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

1.490 atm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D 1.490 atm
$\frac{r_{m i x}}{r_{S O_{2}}}$ = $(\frac{M_{S O_{2}}}{M_{m i x}})^{\frac{1}{2}}$
2.56 = $\frac{64}{M_{m i x}}$
$M_{m i x}$ = 25
Let's say mole fraction of $F_{2}$ is $x$
25 = $\frac{38 \times x + (1 - x) \times 19}{1}$
$x = 0.315$
$K_{p} = \frac{(P_{F})^{2}}{P_{F_{2}}}$ = $\frac{(0.685)^{2}}{0.315} = 1.49 a t m$

Suggest Corrections

thumbs-up

1

Similar questions

800^{\circ}

C, the following equilibrium is established as

F_{2} (g) ⇌ 2 F (g)

The composition of equilibrium may be determined by measuring the rate of effusion of the mixture through a pin hole. It is found that at

800^{\circ}

C and 1 atm mixture effuses 1.6 times as fast as

S O_{2}

effuses under the similar conditions. (Atomic weight of F =19 amu). What is the value of

K_{p}

?

800^{\circ}

C, the following equilibrium is established as

F_{2} (g) ⇌ 2 F (g)

The composition of equilibrium may be determined by measuring the rate of effusion of the mixture through a pin hole. It is found that at

800^{\circ}

C and 1 atm mixture effuses 1.6 times as fast as

S O_{2}

effuses under the similar conditions. (Atomic weight of F =19 amu). What is the value of

K_{p}

?

800 ° C

, the following equilibrium is established as:

F_{2} (g) ⇌ 2 F (g)

The composition of the equilibrium may be determined by measuring the rate of effusion of the mixture through a pinhole. It is found that at

800 ° C

1 atm

the mixture effuses

1.6

times as fast as

S O_{2}

effuses under similar conditions

(A t . w t . o f F = 19)

K_{P}

for the equilibrium is

800^{o}

C, the following equilibrium is established as:

F_{2} (g) \to 2 F (g)

The composition of equilibrium may be determined by measuring the rate of effusion of the mixture through a pin hole. It is found that at

800^{o}

1

atm mixture effuses

1.6

times as fast as

S O_{2}

effuses under the similar conditions. (At. wt. of

F = 19

). What is the value of

K_{p}

800^{o} C

, the following equilibrium is established as:

F_{2} (g) ⇌ 2 F (g)

The composition of equilibrium may be determined by measuring the rate of effusion of the mixture through a pinhole. It is found that at

800^{o} C

1

atm mixture effuses

1.6

times as fast as

{S O}_{2}

effuses under the similar conditions. (At.wt. of

F = 19

). What is the value of

K_{p}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Relation between Kp and Kc

Standard XI Chemistry

Join BYJU'S Learning Program

CrossIcon