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Question

# At 800oC, the following equilibrium is established as:F2(g)→2F(g)The composition of equilibrium may be determined by measuring the rate of effusion of the mixture through a pin hole. It is found that at 800oC and 1 atm mixture effuses 1.6 times as fast as SO2 effuses under the similar conditions. (At. wt. of F=19). What is the value of Kp (in atm)?

A
0.315
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B
0.685
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C
0.46
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D
1.49
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Solution

## The correct option is D 1.49VmixVSO2=√MSO2Mmix⇒1.6=√64Mmix⇒Mmix=64(1.6)2=641.6×1.6=25For F2⇌2F⇒Normal molecular weightExp. molecular weight=1+α⇒3825=1+α⇒α=0.52F2(g)⟶2F(g) 1 0 I1−α 2α E Total moles at eqm=1−α+2α=1+α =1+0.52=1.52∴KP=P2FPF2 =(2α/1+α)2P2(1−α)1+αP =4α2P(1+α)(1−α) =4(0.52)2×11−(0.52)2 =1.49

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