CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

At 800C, the following equilibrium is established as
F2(g)2F(g)
The composition of equilibrium may be determined by measuring the rate of effusion of the mixture through a pin hole. It is found that at 800C and 1 atm mixture effuses 1.6 times as fast as SO2 effuses under the similar conditions. (Atomic weight of F =19 amu). What is the value of Kp?

A
0.315 atm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.685 atm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.460 atm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1.490 atm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 1.490 atm
rmixrSO2 = (MSO2Mmix)12
2.56 = 64Mmix
Mmix = 25
Let's say mole fraction of F2 is x
25 = 38× x + (1 x)×191
x=0.315
Kp = (PF)2PF2 = (0.685)20.315 = 1.49 atm

flag
Suggest Corrections
thumbs-up
1
BNAT
mid-banner-image
similar_icon
Similar questions
View More