Question

At ${90}^{o}C$, pure water has $[H{]}^{+}={10}^{-6}M$, if $100mL$ of $0.2MHCl$ is added to $200mL$ of $0.1MKOH$ at ${90}^{o}C$ then $pH$ of the resulting solution will be:

• A. $5$
• B. $6$
• C. $7$
• D. None of these

Answer 1

Answer: (B)

$6$

$20$ meq. of HCl reacts completely with $20$ meq. of KOH. Hence, the final solution is neutral. Thus at ${90}^{\circ }C$, pH$=6$.