Question

At a certain place, the horizontal component of the earth's magnetic field is $B_o$ and the angle of dip is ${45}^o$. The total intensity of the field at that place will be

• A. $B_o$
• B. $\sqrt{2}{B}_o$
• C. $2B_o$
• D. $B_{o}2$

Answer 1

The correct option is B $\sqrt{2}{B}_o$

when $\theta$ is angle of dip
$B_H=B\cos \theta$
therefore,$B=\frac{B_H}{\cos \theta }$
therefore,$B=\sqrt{2}{B}_H=\sqrt{2}{B}_o$
option(B)