You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equilibrium Constant and Standard Free Energy Change

At a certain ...

Question

At a certain temperature, for the reaction $N_{2} + O_{2} ⇌ 2 N O$ ; if K = 0.09 the equilibrium constant for $N O ⇌ \frac{1}{2} N_{2} + \frac{1}{2} O_{2}$ is:

0.03

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3.3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 3.3
The equilibrium constant for the reaction is given as 0.09. The equilibrium constant for the reverse reaction is $\frac{1}{k}$ . Now the equation is halved, the value of the equilibrium constant will be $\frac{1}{\sqrt{k}}$
$\frac{1}{\sqrt{0.09}} = 3.3$ .

Suggest Corrections

Similar questions

N_{2} + O_{2} ⇌ 2 N O

N O ⇌ \frac{1}{2} N_{2} + \frac{1}{2} O_{2}

K_{C}

N_{2} + O_{2} ⇌ 2 N O

1.6 \times 10^{- 3}

K_{P}

N O ⇌ 1 / 2 N_{2} + 1 / 2 O_{2}

K_{1}

K_{2}

N_{2} + O_{2} ⇌ 2 N O

\frac{1}{2} N_{2} + \frac{1}{2} O_{2} ⇌ N O

N_{2}

O_{2} ⇋ 2 N O

N O ⇋ \frac{1}{2} N_{2} + \frac{1}{2} O_{2}

K_{1}

K_{2}

N_{2} + O_{2} ⇌ 2 N O

\frac{1}{2} N_{2} + \frac{1}{2} O_{2} ⇌ N O

Join BYJU'S Learning Program