At a certain temperature, for the reaction N2+O2⇌2NO; if K = 0.09 the equilibrium constant for NO⇌12N2+12O2 is:
A
0.03
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B
3.3
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C
81
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D
27
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Solution
The correct option is B 3.3 The equilibrium constant for the reaction is given as 0.09. The equilibrium constant for the reverse reaction is 1k. Now the equation is halved, the value of the equilibrium constant will be 1√k 1√0.09=3.3.