At a certain time a tree 6 m high casts a shadow of length 8 metres. At the same time a pole casts a shadow of length 20 metres. Find the height of the pole.

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Solution

(Height of tree) : (height of its shadow) = (height of the pole) : (height of its shadow)

Suppose that the height of pole is x cm.

Then, 6 : 8 = x : 20

⇒ x = $\frac{6 \times 20}{8} = 15$
∴ Height of the pole = 15 cm

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At a certain time a tree 6 m high casts a shadow of length 8 metres. At the same time a pole casts a shadow of length 20 metres. Find the height of the pole.

(Height of tree) : (height of its shadow) = (height of the pole) : (height of its shadow) Suppose that the height of pole is x cm. Then, 6 : 8 = x : 20 ⇒ x = 6×208 = 15 ∴ Height of the pole = 15 cm

(Height of tree) : (height of its shadow) = (height of the pole) : (height of its shadow)

Suppose that the height of pole is x cm.

Then, 6 : 8 = x : 20

⇒ x = $\frac{6 \times 20}{8} = 15$
∴ Height of the pole = 15 cm