At a constant pressure P, the plot of volume (V) as a function of temperature (T) for 2 moles of an ideal gas gives a straight line with a slope $0.328 L K^{- 1}$ . The value of P (in atm) is closest to [Gas constant, $R = 0.0821 L a t m m o l^{- 1} K^{- 1}$ ]

0.25

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0.5

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Solution

The correct option is B 0.5
$P V = n R T \Rightarrow \frac{V}{T} = \frac{n R}{P} = s l o p e P = \frac{n R}{s l o p e} = \frac{2 \times 0.0821}{0.328} = 0.5 a t m$

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