At a constant temperature- a certain mass of gas occupies 7-5 lt- when the pressure is 800mm of Hg- nbsp- Calculate the pressure at which the volume of the gas decreases by 35

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Standard IX

Chemistry

The Ideal Gas Equation

At a constant...

Question

At a constant temperature, a certain mass of gas occupies 7.5 lt. when the pressure is 800mm of Hg. Calculate the pressure at which the volume of the gas decreases by 35% of its initial volume.

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Solution

$A s p r e s s u r e a n d v o l u m e a r e r e l a t e d a t c o n s \tan t t e m p e r a t u r e, t h e l a w u s e d i s B o y l e' s l a w A c c o r d i n g t o B o y l e' s l a w, P_{1} V_{1} = P_{2} V_{2} 800 \times 7.5 = P_{2} \times (7.5 \times 0.65) [A s t h e v o l u m e d e c r e a s e s b y 35 %, t h e r e m a i n i n g v o l u m e i s 65 % o f 7.5 L) P_{2} = \frac{800 \times 7.5}{7.5 \times 0.65} = 1230.77 a t m$

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At a constant temperature, a certain mass of gas occupies 7.5 lt. when the pressure is 800mm of Hg. Calculate the pressure at which the volume of the gas decreases by 35% of its initial volume.

As pressure and volume are related at constant temperature, the law used isBoyle's lawAccording to Boyle's law,P1V1 = P2V2800 × 7.5 = P2 × (7.5 × 0.65) [ As the volume decreases by 35 % , the remaining volume is 65 % of 7.5 L)P2 = 800 × 7.5 7.5 × 0.65 = 1230.77 atm