Question

At a gold shop’s annual promotion, gold coins are distributed with each purchase.The higher the purchase, the higher the value of the gold coin. The value of the gold coin is directly proportional to the thickness and square of the diameter of the coin.Two gold coins are given to a customer. The value of coin1: coin 2 = 4:1. The diameter of the coins are in a ratio 4:3. Find the ratio of the thickness of the coins?

• A. 9 : 6
• B. 11 : 7
• C. 9 : 4
• D. 12 : 5

Answer 1

The correct option is C 9 : 4

$\frac{Thicknes{s}_1\times di{a}_1^2}{Thicknes{s}_2\times di{a}_2^2}=\frac{4}{1}\frac{Thicknes{s}_1}{Thicknes{s}_2}=\frac{4}{1}\times \frac{9}{16}=\frac{9}{4}$