Question

At a particular temperature, the ratio of equivalent conductance to specific conductance of a $0.01N$ NaCl solution is :

• A. ${10}^{5}c{m}^3$
• B. ${10}^{3}c{m}^3$
• C. $10c{m}^3$
• D. ${10}^{5}c{m}^2$

Answer 1

Answer: (A)

${10}^{5}c{m}^3$

At a particular temperature, the ratio of equivalent conductance to specific conductance of a 0.01 N NaCl solution is ${10}^{5}c{m}^3$

${\Lambda }_{eq}=\frac{1000\kappa }{N}$

$\frac{{\Lambda }_{eq}}{\kappa }=\frac{1000}{0.01}={10}^{5}c{m}^3.e{q}^{-1}$