The resistance of $0.01 N$ solution at $25^{\circ}$ is $200 o h m$ . Cell constant of the conductivity cell is unity. Calculate the equivalent conductance of the solution.

200 o h m^{- 1} c m^{2} e q^{- 1}

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300 o h m^{- 1} c m^{2} e q^{- 1}

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400 o h m^{- 1} c m^{2} e q^{- 1}

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500 o h m^{- 1} c m^{2} e q^{- 1}

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Solution

The correct option is B $500 o h m^{- 1} c m^{2} e q^{- 1}$ .
since, we have
$c o n d u c t a n c e * c e l l c o n s t a n t$ = specific conductance
cell consyant = 1
conductance = specific conductance= $\frac{1}{200}$

equivalent conductance= $\frac{K * 1000}{N}$ $S c m^{2} e q^{- 1}$

equivalent conductance= $\frac{1 * 1000}{200 * 0.01}$

equivalent conductance= $500$ $S c m^{2} e q^{- 1}$

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The resistance of 0.01 N solution at 25∘ is 200 ohm. Cell constant of the conductivity cell is unity. Calculate the equivalent conductance of the solution.

The correct option is B 500 ohm−1cm2eq−1.since, we haveconductance∗cellconstant = specific conductancecell consyant = 1conductance = specific conductance= 1200equivalent conductance= K∗1000N Scm2eq−1equivalent conductance= 1∗1000200∗0.01equivalent conductance= 500 Scm2eq−1

The resistance of $0.01 N$ solution at $25^{\circ}$ is $200 o h m$ . Cell constant of the conductivity cell is unity. Calculate the equivalent conductance of the solution.