Question

At a temperature $TK$, the pressure of 4.0 $g$ of argon in a bulb is $p$. The bulb is put in a bath having temperature higher by 50 $K$ than the first one. 0.8 $g$ of argon gas had to be removed to maintain original pressure. The temperature $T$ is equal to :

Answer 1

As we know, $PV=nRT$.
Here, initially $P$ & $V$ are equal to final P&V so, $nRT$ (initial) $=nRT$ (final).
$\left(4/x\right)RT=(4-0.8)/x\times R(T+50)$
$T=200K$.