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Byju's Answer

Standard XII

Chemistry

Ideal Gas Equation

At a temperat...

Question

At a temperature ' $T$ ' $K$ , the pressure of 4.0 $g$ of argon in a bulb is $p$ . The bulb is put in a bath having temperature higher by 50 $K$ than the first one. 0.8 $g$ of argon gas had to be removed to maintain original pressure. The temperature $T$ is equal to:

510

K

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200

K

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100

K

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K

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Solution

The correct option is C 200 $K$
As we know, $P V = n R T$ .
Here, initially $P$ & $V$ are equal to final $P$ & $V$ so, $n R T$ (initial) $= n R T$ (final).
$(4 / x) R T = (4 - 0.8) / x \times R (T + 50)$
$T = 200$ $K$ .

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At a temperature 'T' K, the pressure of 4.0 g of argon in a bulb is p. The bulb is put in a bath having temperature higher by 50 K than the first one. 0.8 g of argon gas had to be removed to maintain original pressure. The temperature T is equal to:

The correct option is C 200 KAs we know, PV=nRT.Here, initially P & V are equal to final P & V so, nRT (initial) =nRT (final).(4/x)RT=(4−0.8)/x×R(T+50)T=200 K.

At a temperature ' $T$ ' $K$ , the pressure of 4.0 $g$ of argon in a bulb is $p$ . The bulb is put in a bath having temperature higher by 50 $K$ than the first one. 0.8 $g$ of argon gas had to be removed to maintain original pressure. The temperature $T$ is equal to:

The correct option is C 200 $K$
As we know, $P V = n R T$ .
Here, initially $P$ & $V$ are equal to final $P$ & $V$ so, $n R T$ (initial) $= n R T$ (final).
$(4 / x) R T = (4 - 0.8) / x \times R (T + 50)$
$T = 200$ $K$ .