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Boyle's Law

At ..... atm ...

Question

At ..... atm of pressure, the volume of a gas will be double than that at 5 atm pressure at a constant temperature.

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Solution

According to Boyel's law, $\frac{P_{1}}{P_{2}} = \frac{V_{2}}{V_{1}} .$
$P_{1} = 5 a t m V_{1} = V m l V_{2} = 2 V m l (A s v o l u m e d o u b l e d)$ $\frac{P_{1}}{P_{2}} = \frac{V_{2}}{V_{1}} ⟹ \frac{5}{P_{2}} = \frac{2 V}{V} P_{2} = \frac{5}{2} = 2.5 a t m$

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