At constant P of 0.0821atmlogV v/s logT graph is plotted for 3 samples of ideal gas as shown. The value of moles of gas in these three samples is respectively:
(Given:log1=0,log2=0.3010,log3=0.4771)
A
3,1,12
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B
12,1,3
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C
1,12,3
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D
12,3,1
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Solution
The correct option is A3,1,12 VT=constant(k)logV=logT+logkwhere k =nRP for 2 graph lognRP=0=log1nRP=1(R=P)orn=1mol For 1 graph lognRP=log3orn=3 For 3 graph lognRP=−log2=log12n=12mol