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Question

At constant P of 0.0821 atm logV v/s log T graph is plotted for 3 samples of ideal gas as shown. The value of moles of gas in these three samples is respectively:


(Given:log 1=0, log 2=0.3010, log 3=0.4771)

A
3,1,12
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B
12,1,3
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C
1,12,3
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D
12,3,1
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Solution

The correct option is A 3,1,12
VT=constant(k)logV=logT+logk where k =nRP
for 2 graph
lognRP=0=log1nRP=1 (R=P) or n=1 mol
For 1 graph
lognRP=log3 or n=3
For 3 graph
lognRP=log2=log12n=12 mol

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