At constant temperature and 200 $m m$ pressure, the volume of a gas is 4 liters. If the pressure is changed to 800 $m m$ , the volume of the gas in liters will be:

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Solution

The correct option is D 1
Since the temperature remains constant, Boyle's law is applicable.
This means that,
$P_{1} V_{1} = P_{2} V_{2}$
Here, $P_{1} = 200 m m$
$V_{1} = 4 L$
$P_{2} = 800 m m$
$V_{2} = ? m l$
Putting all the values, we get $V_{2} = 1 L$ .

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At constant temperature and 200 mm pressure, the volume of a gas is 4 liters. If the pressure is changed to 800 mm, the volume of the gas in liters will be:

The correct option is D 1Since the temperature remains constant, Boyle's law is applicable.This means that,P1V1=P2V2Here, P1=200mmV1=4LP2=800mmV2=?mlPutting all the values, we get V2=1 L.

At constant temperature and 200 $m m$ pressure, the volume of a gas is 4 liters. If the pressure is changed to 800 $m m$ , the volume of the gas in liters will be:

The correct option is D 1
Since the temperature remains constant, Boyle's law is applicable.
This means that,
$P_{1} V_{1} = P_{2} V_{2}$
Here, $P_{1} = 200 m m$
$V_{1} = 4 L$
$P_{2} = 800 m m$
$V_{2} = ? m l$
Putting all the values, we get $V_{2} = 1 L$ .