Question

At $0^{o}C$, if enthalpy of fusion of ice is 1365 kcal/mol, the molar entropy change for melting of ice at $0^{o}C$ is?

Answer 1

$\Delta G=\Delta H-T\Delta S$

During melting of ice, the system remains at equilibrium.

Hence, $\Delta G=0$

So, $\Delta S=\frac{\Delta H}{T}=\frac{1365}{273}=5kcalmo{l}^{-1}{K}^{-1}$