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Byju's Answer
Standard XII
Chemistry
Ideal Gas Equation
At low pressu...
Question
At low pressure, the van der waals equation become :
A
P
V
m
=
R
T
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B
P
(
V
m
−
b
)
=
R
T
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C
(
P
+
a
V
2
m
)
V
m
=
R
T
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D
P
=
R
V
m
+
a
V
2
m
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Solution
The correct option is
C
(
P
+
a
V
2
m
)
V
m
=
R
T
At low pressure, the van der waals equation become
(
P
+
a
V
2
m
)
V
m
=
R
T
Hence, Option "C" is the correct answer.
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Similar questions
Q.
Using Van der Waals equation,
[
P
+
a
V
2
]
(
V
−
b
)
=
R
T
, a
t high pressure, the Van der Waals equation gets reduced to :
Q.
If
Z
is a compresibility factor, van der waals equation at low pressure can be written as:
Q.
Virial equation is:
P
V
M
=
R
T
[
A
+
B
V
M
+
C
V
2
M
+
.
.
.
]
, where
A
,
B
,
C
,
.
.
.
are first second, third, ... virial coefficients, respectively, for an ideal gas.
Q.
At low pressures, the van der Waals equation is written as
[
P
+
a
V
2
]
V
=
R
T
. The compressiblity factor of the gas is:
Q.
At low pressures, the van der Waals equation is written as
[
P
+
a
V
2
]
V
=
R
T
The compressibility factor is then equal to :
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