Question

At. $N.T.P.28g$ of Nitrogen occupies $22.4litres$. What is the mass of $5.6litres$ of Nitrogen at $38cm$ of $Hg$pressure and ${273}^{o}C$ temperature

• A. $7g$
• B. $48g$
• C. $1.75g$
• D. $1.5g$

Answer 1

Answer: (A)

$7g$

the condition 76cm Hg at ${273}^{\circ }$ refer to NTP at NTP,

28g of $N_2\equiv$ 1 mol of $N_2$ occupies 22.4L.

so,5.6L $\equiv \frac{22.4}{5.6}=\frac{1}{4}$ mole of $N_2$ at NTP.

mass of $N_2=\frac{1}{4}\times 28=7g$