At NTP, density of a gas is $0.00045 g / m L$ .The vapour density and molecular weight will be:

5, 10

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15, 20

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35, 20

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10, 5

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Solution

The correct option is D $5, 10$
At NTP condition,
$P = 1 a t m$
$T = 273 K$
$d = 0.00045 g / m L = 0.45 g / L$

From Ideal gas law equation:
$P M = d R T$

$M = \frac{0.45 \times 0.082 \times 273}{1}$

$M = 10 g m$

Also, vapour density $= \frac{m}{2}$
$∴ V a p o u r d e n s i t y = 5$

Hence, option A is correct.

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At NTP, density of a gas is 0.00045g/mL.The vapour density and molecular weight will be:

The correct option is D 5,10At NTP condition,P=1atmT=273Kd=0.00045g/mL=0.45g/LFrom Ideal gas law equation:PM=dRTM=0.45×0.082×2731M=10gmAlso, vapour density =m2∴Vapour density=5Hence, option A is correct.

At NTP, density of a gas is $0.00045 g / m L$ .The vapour density and molecular weight will be: