At rest, a liquid stands at the same level in the tubes. As the system is given an accelearation a towards right. A height difference h occur. The value of h is.

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Solution

REF.Image.
In an accelerated tube, we know,
$t a n θ = \frac{a}{g} = \frac{h}{L}$ [From figure]
$\Rightarrow h = \frac{a L}{g}$ (Reqd)

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