At S.T.P. the volume of a gas is found to be $273 m L$ ? What will be the volume of this gas at $600 m m H g$ and $273^{\circ} C$ ?

391.8 m l

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380 m l

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691.6 m l

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750 m l

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Solution

The correct option is A $691.6 m l$
S.T.P. has T= 273 K and P=1 atm=760 mm of Hg
If V=273 mL at STP then using the relation $\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$
And substituting $P_1=760\ mm\ Hg,\ P_2=600\ mm\ Hg,\ V_1=273\ mL,\ V_2=V\ mL,\ T_1=293\ K\ and\ T_2=273+273=546\ K$
we get:
$\frac{760 \times 273}{273} = \frac{600 \times V}{546}$
$V = 691.6 m L$
Option C is correct.

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At S.T.P. the volume of a gas is found to be 273 mL? What will be the volume of this gas at 600 mm Hg and 273∘C?

At S.T.P. the volume of a gas is found to be $273 m L$ ? What will be the volume of this gas at $600 m m H g$ and $273^{\circ} C$ ?