At STP, number of molecules in $5.6 L$ of sulphur trioxide gas is:

1.5 \times 10^{23}

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3.01 \times 10^{23}

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6.022 \times 10^{23}

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12.044 \times 10^{23}

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Solution

The correct option is A $1.5 \times 10^{23}$
$22.4 L$ of gas correponds to 1 mole, therefore 5.6 L corresponds to 0.25 mole.
Total number of molecules $= m o l e s \times 6.023 \times 10^{23} = 0.25 \times 6.023 \times 10^{23} = 1.5 \times 10^{23}$ .

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Similar questions

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in 100 mL of $0.02 M H_{2} S O_{4}$ solution is.............

(a) $12.044 \times 10^{20}$ molecules (b) $6.022 \times 10^{23}$ molecules

Q. The number of molecules in 89.6 L of a gas at STP are

One mole of oxygen gas at STP is equal to...........

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Q. The weight of gaseous mixture containing

6.02 \times 10^{23}

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At STP, number of molecules in 5.6L of sulphur trioxide gas is:

The correct option is A 1.5×102322.4L of gas correponds to 1 mole, therefore 5.6 L corresponds to 0.25 mole.Total number of molecules =moles×6.023×1023=0.25×6.023×1023=1.5×1023.

At STP, number of molecules in $5.6 L$ of sulphur trioxide gas is:

The correct option is A $1.5 \times 10^{23}$
$22.4 L$ of gas correponds to 1 mole, therefore 5.6 L corresponds to 0.25 mole.
Total number of molecules $= m o l e s \times 6.023 \times 10^{23} = 0.25 \times 6.023 \times 10^{23} = 1.5 \times 10^{23}$ .