Question

At STP the density of $CC{l}_4$ vapour in $\text{g/L}$ will be nearest to:

• A. $6.87$
• B. $3.42$
• C. $10.26$
• D. $4.57$

Answer 1

The correct option is A $6.87$

Weight of 1 mol of $CC{l}_4$ vapour $=12+4\times 35.5=154\text{g}$
$\therefore$
Density of $CC{l}_4$ vapour = $\frac{154}{22.4}{\text{g L}}^{-1}=6.875{\text{g L}}^{-1}$