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Question

At STP volume occupied by 11.2 grams of a gas of vapour density 11.2 in litres will be:

A
22.4
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B
16.8
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C
11.2
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D
5.6
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Solution

The correct option is C 11.2
11.2 g of gas has vapour density = 11.2
We know, Molar mass = 2 × Vapour density (VD)
Molar mass = 2 × 11.2 = 22.4 g/mol
No. of moles of gases = 11.222.4 = 0.5 moles
1 mole of gas occupies 22.4 litres of volume
0.5 moles of gas will occupy 11.2 litres of volume

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