At the height 80 m, an aeroplane is moving with 150 m/s. A bomb is dropped from it so as to hit a target. At what distance from the target should the bomb be dropped (given g = 10 m/s2)
605.3 m
The horizontal distance covered by bomb,
BC=vH×√2hg=150√2×8010=660 m
∴ The distance of target from dropping point of bomb,
AC=√AB2+BC2=√(80)2+(600)2=605.3m