At the height 80 m, an aeroplane is moving with 150 m/s. A bomb is dropped from it so as to hit a target. At what distance from the target should the bomb be dropped (given g = 10 $m / s^{2}$ )

605.3 m

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600 m

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80 m

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230 m

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Solution

The correct option is A
605.3 m

The horizontal distance covered by bomb,
$B C = v_{H} \times \sqrt{\frac{2 h}{g}} = 150 \sqrt{\frac{2 \times 80}{10}} = 660 m$

$∴$ The distance of target from dropping point of bomb,
$A C = \sqrt{A B^{2} + B C^{2}} = \sqrt{(80)^{2} + (600)^{2}} = 605.3 m$

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At the height 80 m, an aeroplane is moving with 150 m/s. A bomb is dropped from it so as to hit a target. At what distance from the target should the bomb be dropped (given g = 10 m/s2)

The correct option is A 605.3 m The horizontal distance covered by bomb, BC=vH×√2hg=150√2×8010=660 m ∴ The distance of target from dropping point of bomb, AC=√AB2+BC2=√(80)2+(600)2=605.3m

At the height 80 m, an aeroplane is moving with 150 m/s. A bomb is dropped from it so as to hit a target. At what distance from the target should the bomb be dropped (given g = 10 $m / s^{2}$ )

The correct option is A
605.3 m

The horizontal distance covered by bomb,
$B C = v_{H} \times \sqrt{\frac{2 h}{g}} = 150 \sqrt{\frac{2 \times 80}{10}} = 660 m$

$∴$ The distance of target from dropping point of bomb,
$A C = \sqrt{A B^{2} + B C^{2}} = \sqrt{(80)^{2} + (600)^{2}} = 605.3 m$