At very high pressure, the van der Waals equation reduces to :

P V = R T + P b

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P V = \frac{a R T}{V^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P = \frac{R T}{V - b}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P V = R T - \frac{a}{V}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A $P V = R T + P b$
C $P = \frac{R T}{V - b}$
At very high pressure, the van der Waals equation reduces to
$P V = R T + P b$
$P = \frac{R T}{V - b}$
At high pressures, volume $V$ is quite small and the term b cannot be neglected in comparison to $V .$ Although the term $a / V^{2}$ is quite large, it is so small in comparison to $P$ that it can be neglected. Hence, the van der waals equation reduces to
$P (V - b) = R T$
$P V = R T + P b$
and $P V - P b = R T$
$P (V - b) = R T$
$P = \frac{R T}{V - b}$

Suggest Corrections

Similar questions

[P + \frac{a}{V^{2}}] (V - b) = R T

Column A	Column B
(A) High pressure	(i) $P V = R T + P b$
(B) Low pressure	(ii) $P V = R T - \frac{a}{V}$
(C) $P \to 0$	(iii) $P V = R T$
(D) Neither $a$ nor $b$ is negligible	(iv) $(P + \frac{a}{V^{2}}) (V - b) = R T$

[P + \frac{a}{V^{2}}] V = R T

[P + \frac{a}{V^{2}}] V = R T

mole

2

1

\begin{matrix} Column 1 & Column 2 A & At low pressure & i & P (V - b) = R T B & At high pressure & i i & (P + \frac{a}{V^{2}}) V = R T C & At low pressure and high temperature & i i i & P V = R T D & At room temperature and pressure & i v & (P + \frac{a}{V^{2}}) (V - b) = R T \end{matrix}

Join BYJU'S Learning Program