Question

At what angle the hands of a clock are inclined at 15 minutes past 5 ?

• A. ${58.5}^o$
• B. ${64}^o$
• C. ${67.5}^o$
• D. ${72.5}^o$

Answer 1

Answer: (C)

${67.5}^o$

Angle traced by hour hand in 12 hours = ${360}^o$

Therefore, angle traced by hour hand in $5\frac{15}{60}$ hrs = ${157.5}^o$

Angle traced by hour hand in 60 min = ${360}^o$

Therefore, angle traced by hour hand in 15 min = $(\frac{360}{60}\times 15{)}^o={90}^o$

Required angle = ${157.5}^o-{90}^o={67.5}^o$