Question

At what temperature the reading on Kelvin scale is three times that on Celsius scale

Answer 1

We know,

$k-273=C$

Divide the equation by 100
$\frac{(K-273)}{100}=\frac{(C-0)}{100}$

According to question ,
$K=3C$
so,
$\frac{(3C-273)}{100}=\frac{C}{100}$

$3C-273=C$

$2C=273$

$C=136.5°C$

$\Rightarrow 136.5\times 3=409.5$

$\Rightarrow {136.5}^{o}C+273=409.5K$

∴ The temperature of the reading on the Kelvin scale is three times that on the Celcius scale at 136.5 ${}^0$C or 409.5K.