Atomic numbers of nitrogen, oxygen and fluorine are 7, 8 and 9 respectively. Write the electronic configuration of each element and answer the following question:
What is the period number of O in the periodic table?
Atomic numbers of nitrogen, oxygen and fluorine are 7, 8 and 9 respectively. Write the electronic configuration of each element and answer the following question:
What is the period number of O in the periodic table?
Step-1: Introduction
The elements in periodic table are placed in periods and groups. Periods are horizontal rows that has increasing atomic numbers. Groups are vertical columns. There are 7 periods and 18 groups in periodic table.
Step-2: Electronic configuration
Atomic numbers of Nitrogen (), Oxygen () and Fluorine () are 7, 8 and 9 respectively.
Electronic configuration of Nitrogen = (2, 5)
Electronic configuration of Oxygen = (2, 6)
Electronic configuration of Fluorine = (2, 7)
Step-3: Period of Oxygen
Oxygen has 2 electrons in K-shell and 6 electrons in L-shell that has 2 valence shells.
Number of valence shell = Number of period
So, period number is 2.
Therefore, the period number of Oxygen in the periodic table is 2.
Step-1: Introduction
The elements in periodic table are placed in periods and groups. Periods are horizontal rows that has increasing atomic numbers. Groups are vertical columns. There are 7 periods and 18 groups in periodic table.
Step-2: Electronic configuration
Atomic numbers of Nitrogen (), Oxygen () and Fluorine () are 7, 8 and 9 respectively.
Electronic configuration of Nitrogen = (2, 5)
Electronic configuration of Oxygen = (2, 6)
Electronic configuration of Fluorine = (2, 7)
Step-3: Period of Oxygen
Oxygen has 2 electrons in K-shell and 6 electrons in L-shell that has 2 valence shells.
Number of valence shell = Number of period
So, period number is 2.
Therefore, the period number of Oxygen in the periodic table is 2.
