Atomic weight of barium is $137.34$ . The equivalent weight of barium in $B a C r O_{4}$ which is used as an oxidising agent in acid medium is:

137.34

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45.78

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114.45

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68.67

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Solution

The correct option is B $45.78$
$C r O_{4}^{2 -}$ (and not $B a^{2 +}$ ) is involved as an oxidizing agent and hence, is reduced to $C r^{3 +}$ ,
Hence, $E w = \frac{M w}{3} = 45.78$

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Atomic weight of barium is 137.34. The equivalent weight of barium in BaCrO4 which is used as an oxidising agent in acid medium is:

The correct option is B 45.78CrO2−4 (and not Ba2+) is involved as an oxidizing agent and hence, is reduced to Cr3+, Hence, Ew=Mw3=45.78

Atomic weight of barium is $137.34$ . The equivalent weight of barium in $B a C r O_{4}$ which is used as an oxidising agent in acid medium is:

The correct option is B $45.78$
$C r O_{4}^{2 -}$ (and not $B a^{2 +}$ ) is involved as an oxidizing agent and hence, is reduced to $C r^{3 +}$ ,
Hence, $E w = \frac{M w}{3} = 45.78$