Atoms of element B form HCP lattice and those of element A occupy two thirds of tetrahedral voids. The formula of the compound is .

A_{4} B_{3}

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A_{4} B_{6}

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A_{8} B_{3}

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Solution

The correct option is A $A_{4} B_{3}$
The number of tetrahedral voids formed is equal to twice the number of atoms of element B. But only 2/3 of these tetrahedral voids are occupied by atoms of element A.

Therefore the ratio of number of atoms of A and B is

2x(2/3) : 1 = 4:3

The formula of compound is $A_{4} B_{3}$

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Atoms of element B form HCP lattice and those of element A occupy two thirds of tetrahedral voids. The formula of the compound is .

The correct option is A A4B3The number of tetrahedral voids formed is equal to twice the number of atoms of element B. But only 2/3 of these tetrahedral voids are occupied by atoms of element A. Therefore the ratio of number of atoms of A and B is 2x(2/3) : 1 = 4:3 The formula of compound is A4B3