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B
X=NaBH4,Y=NaB3H4,Z=H2
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C
X=NaB3H4,Y=NaBH4,Z=H2
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D
X=NaBH4,Y=NaB3H8,Z=H2
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Solution
The correct option is DX=NaBH4,Y=NaB3H8,Z=H2 Reduction of diborane can be accomplished with Na or sodium borohydride. 2B2H6+2Na→NaBH4+NaB3H8 B2H6+NaBH4→NaB3H8+H2