b........abbc.......bbca...........bcabb..........ab

acaa

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acba

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cabc

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cacc

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Solution

The correct option is C cabc
$b c - a b / b c a - - b / b c a b - / b a c b / b c - a b$ .

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Similar questions

b _ abbc _ bbca _ bcabb _ ab

∣ ∣ ∣ ∣ ∣ \begin{matrix} b c - a^{2} & c a - b^{2} & a b - c^{2} - b c + c a + a b & b c - c a + a b & b c + c a - a b (a + b) (a + c) & (b + c) (b + a) & (c + a) (c + b) \end{matrix} ∣ ∣ ∣ ∣ ∣ = 3. (b - c) (c - a) (a - b) (a + b + c) (a b + b c + c a)

A . . . . . . B B C . . . . A A B . . . . . C C A . . . . . B B C C

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