Question 66 (b)

Find the value of the given polynomial at a = -2 and b = 3.

$a^{2} - 2 a b + b^{2}$

Open in App

Solution

Given, a = -2 and b = 3
So, putting a = -2 and b = 3 in the given expression, we get
$a^{2} - 2 a b + b^{2} = (- 2)^{2} - 2 (- 2) (3) + (3)^{2} = 4 + 12 + 9 = 25$

Suggest Corrections

Similar questions

Question 66 (f)

Find the value of the given polynomial at a = -2 and b = 3.

$\frac{a^{2} - b^{2}}{3}$

Question 66 (h)

Find the value of the given polynomial at a = -2 and b = 3.

$a^{2} + b^{2} - a b - b^{2} - a^{2}$

Question 66 (e)

Find the value of the given polynomial at a = -2 and b = 3.

$\frac{a^{2} + b^{2}}{3}$

Question 66 (g)

Find the value of the given polynomial at a = -2 and b = 3.

$\frac{a}{b} + \frac{b}{a}$

Question 66 (c)

Find the value of the given polynomial at a = -2 and b = 3.

$a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}$

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program